计算了引起电离能量沉积的五种概率。

Five probabilities of causing ionization deposited energy are calculated.

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该系统还包括具有用于发射电离能量的第二原子种类的源。

The system also includes a source having a second atomic species for emitting an ionizing energy.

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可以提供滤波器用于在接近特征发射峰值的区域之外的区域阻挡来自源的电离能量。

A filter may be provided for blocking ionizing energy from the source in regions other than a region proximate the characteristic emission peak.

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So if we can figure out the binding energy, we can also figure out how much energy we have to put into our atom in order to a eject or ionize an electron.

所以如果我们可以计算出结合能，我们也可以计算出,我们需要注入多少能量到原子中,去逐出或电离一个电子。

麻省理工公开课 - 化学原理课程节选

The reason it's aluminum is because aluminum has a lower z effective, so it's not being pulled in as tightly by the nucleus, and if it's not being pulled in as tightly, you're going to have to put in less energy in order to ionize it, so that's why it's actually going to have the smaller ionization energy.

原因是,铝的有效核电量更少，所以没有被原子核束缚得更紧，而如果没有被束缚得更紧，你为了电离它所需要注入的能量也就更少，这就是,它的电离能会更低的原因。

麻省理工公开课 - 化学原理课程节选

So you don't want to put in a negative energy, that's not going to help you out, you need to put in positive energy to get an electron out of the system. So that's why you'll find binding energies are always negative, and ionization energies are always going to be positive, or you could look at the equation and see it from there as well.

因为这对电离没有帮助,你需要一个正的能量,使得电子脱离这个系统,这就是为什么你会发现,结合能总是负的而电离能总是正的,或者你们看这个方程也可以发现这一点。

麻省理工公开课 - 化学原理课程节选