Bezier曲面（具体类为Geom_BezierSurface）也是一个有界曲面（bounded surface），因为他由Geom_BoundedSurface派生。这两种曲面还都是曲面（抽象类Geom_Surface）。
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So, and similarly, if I take any other loop that avoids the origin, I can find, actually, a surface bounded by it that does not pass through the origin.
类似的，对于任何不经过原点的环路，都能找到一个以之为界的曲面，该曲面不经过原点。
Can I find a surface that's bounded by this loop and that does not pass through the origin?
能找到一个以该环路为界，且不经过原点的曲面吗？
OK, so one way to find a surface that's bounded by this curve is to take what's called the Mobius strip.
这条曲线界定的曲面叫,叫做Mobius带。
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