If the implementation is just a bit insecure, a hole is opened on the boundary: the balloon deflates or, worst case, explodes.

如果实现不是很安全，那么这个边界上就会出现漏洞：导致气球消气了，或者最糟糕的情况是气球炸了。

youdao

You've got to place the boundary at exactly the right place, otherwise you've got a bit too much in your system or a bit too little.

你要把边界，设置在正确的位置上，否则你的系统就会要么多出一部分，要么少一部分。

youdao

So specifying a -m128bit-long-double will align "long double" to a 16-byte boundary by padding the "long double" with an additional 32-bit zero.

因此指定一个- m 128bit - long - double会将“long double”按照16字节边界进行对齐，它会为“long double”填充32位的0。

youdao

You've got to place the boundary at exactly the right place, otherwise you've got a bit too much in your system or a bit too little.

你要把边界,设置在正确的位置上，否则你的系统就会要么多出一部分,要么少一部分。

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