我们将在早上8点半步行离开，下午5点乘公共汽车返回。
We will leave at 8:30 in the morning on foot and return at 5 o'clock in the afternoon by bus.
我们把A的行，和x的列做点乘。
We do a dot products between the rows of a and the columns of X.
那么乘积法则对点乘求导没问题。
So, product rule is OK for taking the derivative of a dot product.
当点乘的数量积为零时,这两个向量垂直。
These two vectors are perpendicular exactly when their dot product is zero.
下面是方法,像点乘中一样，是个几何方法。
Now comes my method number two as we had with the dot product, is a geometrical method.
他将于七点乘直达列车到北京。
呃，我们学过怎么用点乘,来判断两个向量是否垂直。
Well, we've learned how to detect whether two vectors are perpendicular to each other using dot product.
如果你用i做点乘，你能得到第一个分量,那就是x1，1*x1+0
If you do the dot product with i hat, you will get the first component 0 that will be x1. One times x1 plus zero, zero.
抱歉。。。，这里有个点乘符号，可能不太明显，但是这个点很重要。
Sorry, there's a dot here that maybe is not very big, but it's very important.
并且与设计的点乘硬件芯片一起构成了一种椭圆曲线公钥制密码系统。
And it works together with a new hardware chip to get a elliptic curve public-key cryptosystem.
如果你要找到，这个位置的数是什么，那你就往左，和往上看，然后用它们做点乘。
And, if you want to find what goes in a given slot here, then you just look to its left and you look above it, and you do the dot product between these guys.
椭圆曲线点乘的实现速度决定了椭圆曲线密码算法(ECC)的实现速度。
The implementation speed of elliptic curve Cryptography (ECC) depends on the implementation speed of elliptic curve point multiplication.
利用现有的公式对雅可比矩阵中的元素进行改写，将矢量叉乘变为矢量点乘。
After the formula of documents are used to rewrite elements of Jacobian matrix, the vector cross product is changed into the vector dot product in Jacobian matrix.
函数空间点乘子的刻划对研究函数空间算子理论和函数空间性质有着直接的意义。
To characterize the pointwise multiplier of function space has the direct meaning to study the operator theory and property of function space.
为了提高椭圆曲线密码（ECC）的点乘运算速度，提出了一种快速约简求模算法。
To accelerate point multiplication operation of elliptic curve cryptography(ECC), a fast reduction algorithm for modular operation was introduced.
经常，她早7点乘公交车去学校，教学，办公，与其他的助教们一起吃午饭，然后去听课。
On a typical day, she takes a bus into campus at 7 am, teaches, holds office hours, has lunch with other teaching assistants, and then attends her own classes.
主要的实现部分包括椭圆曲线上点加与点乘运算的实现和各个功能模块算法流程的实现。
The realization of the main part contains the implementation of point addition and multiplication based on elliptic curves and the achievement the process of functional blocks.
还有个很有趣的现象要注意一下，就是我们可以用乘积法则,对向量表达式求导，无论是点乘或叉乘。
OK, now, so there's an interesting thing to note, which is that we can use the usual product rule for derivatives with vector expressions, with dot products or cross products.
其次文章详细论述了ECC的相关知识及从倍点乘算法和标量乘运算两方面来提高该算法的运算效率。
Secondly, it analyzed ECC and how to improve the algorithm efficiency from the point of Times-dot algorithm and scalar multiplication algorithm.
采用改进的算法针对二进制方法点乘的椭圆曲线密码进行了符号变换故障攻击，利用仿真实验进行了验证。
Using the improved algorithm, we present the attack on elliptic curve cryptosystems with binary scalar multiplication, and verify it through software simulation.
乘波体是一种由已知超声速或高超声速流场生成的气动构形，在设计点乘波体构型的整个前缘产成贴附的激波。
A wave rider is a configuration designed such that the bow shock generated by the shape is perfectly attached along the leading edge at the design condition.
我们得乘半夜12点的火车。
一切都定下来了—我们乘九点的航班走。
亨利爵士和我商定星期六乘10点半的火车。
为了能在八点半准时开他的小店，他需要在6点离开公寓。毕竟，他得先坐公共汽车，然后再乘地铁。
To arrive in time to open his tiny store at 8:30, he need to leave our apartment at 6. After all, he had to take a bus and then the subway.
我们在伦敦买了一辆旧车，一路开到喀布尔，然后把它卖了换回一点小钱，然后一路上能乘什么车就乘什么车继续向东前进。
We’d bought an old car in London, driven it all the way to Kabul, sold it for a small profit, and carried on east by whatever transport came our way.
这一关，你有一个小型的小队，并要求潜入一个基地，杀点人，干掉一个敌人的直升机，然后乘一辆偷来的车辆离开。
It's a level where you have a small squad and are required to infiltrate a base, kill some dudes, knock out an enemy helicopter, and then escape in a stolen vehicle.
我们周四下班后大约6点见面好吗？我们可以乘出租车一起去参加晚会。
A Good. Shall we meet after work on Thursday, about 6? We can catch a taxi together to the party.
比如 10 米乘 10 米的网格，取每个交叉点的值（共有 100组）就形成一个光栅数据集。
Taking a 10-meter-by-10-meter grid and making one observation for each intersection (100 observations) would constitute a raster dataset.
比如 10 米乘 10 米的网格，取每个交叉点的值（共有 100组）就形成一个光栅数据集。
Taking a 10-meter-by-10-meter grid and making one observation for each intersection (100 observations) would constitute a raster dataset.
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