-
The ideal thing would be that the mutual fund does these calculations and it puts it all together for you.
最理想的事情是,共同基金会做一些这样的计算,再为你们把这些数据综合起来。
-
And the answer is, unlike many, unlike commercially generated computers, the brain works through parallel processing, massively parallel distributed processing.
问题的答案是这样的,与出于商业目的而制造的计算机不同,大脑采用并行加工的方式处理信息,采用广泛分布的并行加工
-
Which is, answers can be wrong.
如果计算机显示是这样的。
-
So what that means is the compiler is actually going to first "cast" so to speak 13 from whatever it is - to a float -- to a floating point value -- and then perform the division for us.
所以这里的意思是编译器将,做“计算“，譬如13这样一个浮点数,-到另一个浮点数-,然后为我们处理除法。
-
I'm going from V2 to V2 dv - what do you think this integral is? Right, W1 so this is easy part, zero here.
这样才保证了过程的可逆性,下面来计算，路径1的功。
-
And we can go through and calculate the value of this quantity in parenthesis. And, when we do so, we get the value 2.18 times 10 to the minus 18 joules.
我们能进行计算这些值,如果我们这样做，我们能算出是，2。18，乘以10，的负18焦耳。
-
You might think that what a computer, what a chess-playing computer does is just this: it calculates every possible branch, every possible game from here on out.
你可能认为,一台电脑,或一台下棋电脑所做的工作就是这样,计算出所有可能的下法,以及与之对应的各种可能的棋局
-
Then to get the monthly payment, you take the square bracketed thing and you divide by the mortgage balance and that's the monthly payment; that's how it's calculated.
如果要算每月偿还额,你用贷款余额,除以这个方括号的值,这样就得出每月偿还额,这就是每月偿还额的计算方法
-
So let's do a sample calculation now using this Rydberg formula, and we'll switch back to emission, and the reason that we'll do that is because it would be nice to actually approve what we just saw here and calculate the frequency of one of our lines in the wavelength of one of the lines we saw.
让我们用Rydberg公式,做一个例题，我们回到发射上,这么做是因为这样,可以用我们看到的波长,来验证我们计算的频率。
-
And so the program may do different things on different runs. We'll see a lot of that, because it's used a lot in modern computing.
因此程序会对不同的输入做不同的操作,我们会看到很多这样的情况，因为它在现代计算中被广泛应用。
-
You might recall from grade school sometimes you put things in parentheses so that your addition happens first, then your multiplication, otherwise multiplication would happen by default first.
你们可能会想起小学时，将一些加法表达式,放在圆括号里，这样加法可以先计算，然后是乘法，否则，乘法默认先发生。
-
This is going to be probably a homework at some point to do this. For now, let's take it for granted. Let's take it for granted that we know how to calculate this derivative from an equation of state like this.
这可能是将来的一个课后作业,现在，请把这当成理所当然的，理所当然地认为我们,知道怎样从一个状态,方程计算这样的微分式。
-
For a couple of reasons. In some ways, this would be nicer, do expected cases, it's going to tell you on average how much you expect to take, but it tends to be hard to compute, because to compute that, you have to know a distribution on input.
关注最快的情况，在某种意义上来说，因为一些原因这样想挺不错的，当我们处理一个给定的问题,计算平均时间的时候,是很难计算的，因为你并不知道输入的分布情况,这些输入会是怎么样的呢？
-
Okay, so when you are working with source material that looks like this, there is in fact no such thing as infinite zoom in computer science.
当我们处理,这样的原数据时，事实上计算机科学中,并不存在无限放大。
-
Well really, the things we've looked at thus far can you do after just a semester of this kind of material and exposure to this particular world.
当结束这样一门课时,你是不是能通过学习和接触计算机科学,也做出我们刚刚看到的这些东西。
-
K/4 We will do it for atomic hydrogen. It is K over four.
在氢原子里这样计算时。
-
And that's when things really get interesting and so this just hints at the types of thinking that one can derive from the field of computer science and apply either to the field itself of computer science, or whatever domain it is that you are here too study.
这样就开始有意思起来了,这仅仅是我们从计算机科学领域,获得的一些思维方式上的启示,这种思维方式不仅适用于计算机科学本身，也同样可以应用在其他的学习领域。
-
But that's not enough because computers at the end 1 of the day only understand 0s and 1s and what you and is clearly not a collection of 0s and 1s.
但是仅仅这样是不够的，计算机,最终只会认识0和,你现在得到的，c的文件显然不是0，1的合集。
-
A If you want to convert a number like 65 to the letter A, you just have tell the computer "cast that int to a char."
如果你要把一个像65这样的数字转换为字母，你只需要告诉计算机“把那个int型数据转换成char型处理“
-
And I can calculate what happens to G under those conditions.
因为在化学反应中组分就是这样变化的,我能够计算在这些条件下G的变化。
-
I mean what if you're running so many things, what if the user has copied and pasted their thesis and just pasted it at the blinking prompt such that you're now out of memory because your computer is somewhat limited in memory so get string cannot possibly return all those characters or fit all of those characters in memory and return to you the address of the first.
如果你运行了很多程序，假使用户复制粘贴了他们的论文,只是粘贴在光标提示符那里,这样就出现了内存不足,因为你们的计算机的内存是有限的,所以GetString不可能返回所有的字符,或者保存这些字符到内存中,并且返回第一个字符的地址。
应用推荐