• Well, if this bond has completely identically equal sharing of electrons, then this bond will be nonpolar.

    如果一根键连的两个原子,键上的电子吸引程度是完全等价的,那么这根键是非极性的。

    麻省理工公开课 - 固态化学导论课程节选

  • What kind of effect do you think video games have on youth or children?

    你认为电子游戏年轻人或者孩子有什么影响呢?

    电子游戏 - SpeakingMax英语口语达人

  • It was a classical model, right, so we could say the electron is exactly this far away from the nucleus.

    这是个经典模型,吧,我们说电子离,原子核就是这么远。

    麻省理工公开课 - 化学原理课程节选

  • If de Broglie is correct, we could then model the electron in its orbit not moving as a particle, but let's model it as a wave.

    如果德布罗意是的,那么我们可以在电子轨道中建立电子模型,不是像粒子一样运动,而是像波一样运动。

    麻省理工公开课 - 固态化学导论课程节选

  • With electronic technology, it's becoming more economical to offer sophisticated financial services to everyone.

    由于电子技术,尖端的金融服务,每个人来说,更为经济

    耶鲁公开课 - 金融市场课程节选

  • So I set about on two missions, the first was to visit high schools around country and talk to young people about their use of digital technology and second was to go online and began to look closely at websites, chat rooms, internet list that young people were creating.

    我为此制定了两个任务,第一个是拜访全国的高中,与年轻人进行交谈,关于他们电子技术的使用,第二个任务就是上网,开始认真研究那些网站,聊天室,以及年轻人们所创造的网络世界。

    麻省理工公开课 - 媒体、教育、市场课程节选

  • As time goes on, we've developed ever more complex machines to study people and we've talked about some of these already: EKG machines, so an example of an electrical device that can be used to monitor a very elaborate function deep inside your body, the beating of your heart and the rhythm of your heart.

    如今,我们已经有功能更加复杂的设备,来研究人类,比如之前说到的心电图,我们使用电子装置,身体内部机能进行精确地监控,具体到心电图就是心跳和心率

    耶鲁公开课 - 生物医学工程探索课程节选

  • And I'm worried about e-mail! Talk about pricking my pomposity.

    电子邮件不行吗,谈论一下我自大的打击。

    耶鲁公开课 - 1945年后的美国小说课程节选

  • Right, we had one from each atom, so that means we need a total of two in our molecular orbital.

    吧,每个原子有一个电子,这意味着在分子轨道里我们一共需要两个电子

    麻省理工公开课 - 化学原理课程节选

  • And let's say our second electron now is really far away, such that it's actually not going to shield any of the nuclear charge at all from that first electron.

    距离原子核非常非常近,我们说第二个电子处于非常远的位置,这样它不会第一个电子,感受到的来自原子核的电荷量有任何屏蔽作用,我们最后要说的是。

    麻省理工公开课 - 化学原理课程节选

  • That's sometimes confusing for people, because it seems like okay, is it a photon or is it an electron.

    有时候这人们来说是令人迷惑的,因为它看起来好像是的,它是一个光子还是一个电子

    麻省理工公开课 - 化学原理课程节选

  • So in oxygen we have a similar situation where, in fact, we are not going to promote any of the electrons because we have two lone pair electrons no matter what we do.

    在氧中,情况很类似,我们不能激发电子,因为无论如何我们都有两个孤电子

    麻省理工公开课 - 化学原理课程节选

  • So in terms of nitrogen that starts off with a valence number of 5, again we have 2 lone pair electrons in the nitrogen, and again, we have 6 electrons that are shared.

    于氮来说,我们应该从五个价电子开始,同样,氮也有两个孤电子,共用电子的个数也一样,是六个。

    麻省理工公开课 - 化学原理课程节选

  • So what that means is that we're limited in any atom to having two electrons per orbital, right, because for any orbital we can either have a spin up electron, a spin down electron, or both.

    这意味着在一个原子内,每个轨道上可以有两个电子吧,因为任何轨道,我们可以有自旋向上或者自选向下或者两者都有。

    麻省理工公开课 - 化学原理课程节选

  • Orbitals of equivalent energy, we strive for unpaired electrons.

    相同能量轨道,我们找到不成电子

    麻省理工公开课 - 固态化学导论课程节选

  • For the sulfur, we start off with 6 valence electrons, minus 4 lone pair electrons, minus 2, taking in account our bonding electrons, so we end up with a formal charge of 0.

    于硫,我们从六个价电子开始,减去四个孤电子,再减去二,算上我们的成键电子,因此最终我们有零个形式电荷。

    麻省理工公开课 - 化学原理课程节选

  • So, if we want to figure out the formal charge on the carbon, we need to take the number of valence electrons, so that's 4. We need to subtract the lone pair, what number is that? It's 2.

    如果我们想算出碳原子的形式电荷,我们需要将价电子的个数,也就是四,减去孤电子的个数,它是多少?是二。

    麻省理工公开课 - 化学原理课程节选

  • We see three bonding pairs so this is a triple bond, indeed a multiple bond.

    我们看到3成键电子所以这是一个三重键,它确实是多重键。

    麻省理工公开课 - 固态化学导论课程节选

  • We figured out the mass is so tiny that it shouldn't really deflect them very much.

    电子的质量这么小,它基本不会产生影响。

    麻省理工公开课 - 化学原理课程节选

  • And then we have a triple bond there because we have 3 pairs of electrons.

    然后那里还有一个三键,因为我们有三电子

    麻省理工公开课 - 化学原理课程节选

  • Place the non-bonding pairs on peripheral atoms first, which the higher average valence electron energy.

    首先将孤电子放在外围的原子,那儿具有较高的平均价电子能。

    麻省理工公开课 - 固态化学导论课程节选

  • So basically, at the time he was just going on size and then traits, but what we actually know today is that we can also order things in the periodic table by electron configuration.

    基本上,在当时他只能通过大小,和特性来进行,但是现在我们已经知道了,我们还可以通过电子排布来它们进行排序。

    麻省理工公开课 - 化学原理课程节选

  • And if we talk about chlorine, and both of the chlorines are the same in this case, we start with a valence number of 7 for chlorine, and then we subtract 6, because it had 6 lone pair electrons around each of the chlorine atoms.

    而如果我们讨论氯的话,在这个例子中两个氯的情况都是一样的,从七个价电子开始,然后减去六,因为每个氯原子周围,都有六个孤电子

    麻省理工公开课 - 化学原理课程节选

  • All right, so I did this not at all purposely, but this can point out for you that you need to make sure that the number of electrons that you have in your molecular orbital does match up with the total number that you have in your atomic orbitals.

    我并不是故意这么做的,但这告诉我们必须要保证,分子轨道里的电子数,和原子轨道里的,总电子数能上。

    麻省理工公开课 - 化学原理课程节选

  • How many electrons in the one electron system, right?

    一个单电子系统中有多少个电子吗?

    麻省理工公开课 - 固态化学导论课程节选

  • And an electron is something where, i n fact, we might be able to, if we calculate it and see how that works out, actually observe some of its wave-like properties.

    如果我们电子做计算,并且知道如何算出来的,那么我们是可以观测到,电子的一些波动性质的。

    麻省理工公开课 - 化学原理课程节选

  • Well, we would have to H+ have one of these hydrogen atoms go to an H plus, * plus an electron, right? **H --> H+ + e-** So, now we have a hydrogen ion here.

    我们先要让,一个氢原子变成氢离子,加上一个电子么*,我们现在有一个氢离子了。

    麻省理工公开课 - 固态化学导论课程节选

  • And step seven is how many electrons do we have left over that are going to go into lone pairs? How many?

    而第七步是我们剩下,多少电子成为孤电子?多少?

    麻省理工公开课 - 化学原理课程节选

  • 0. 26 minus 6, so that tells us 20, and these are all going to be lone pairs.

    二十个,二十六减去六,因此是二十个,它们都会成为孤电子

    麻省理工公开课 - 化学原理课程节选

  • So we need to add those 2 valence electrons left as lone pair electrons in our structure.

    因此我们需要将这两个剩下的价电子,作为孤电子加到我们的结构中。

    麻省理工公开课 - 化学原理课程节选

$firstVoiceSent
- 来自原声例句
小调查
请问您想要如何调整此模块?

感谢您的反馈,我们会尽快进行适当修改!
进来说说原因吧 确定
小调查
请问您想要如何调整此模块?

感谢您的反馈,我们会尽快进行适当修改!
进来说说原因吧 确定