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STUDENT: Right, we're going to do that in a second, but the answer is Fibonacci numbers, we define the first two.
学生：听不见：,我们马上会试一试，但是答案是斐波那契数列，我们可以定义下最初的两个数。
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The basic idea is, you take a guess and you -- whoops -- and you find the tangent of that guess.
首先取个猜想数,然后，嗯,去取猜想数那儿的切线。
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He came up with the relationship that nu bar, which is called wave number --He found the reciprocal.
他也提出了它们与波数的关系，波数是波长的倒数。
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Similarly, the so-called five books of Moses--Genesis, Exodus, Leviticus,Numbers, Deuteronomy, nowhere claim to have been written in their entirety by Moses.
同样地，所谓的摩西五经--《创世纪》,《出埃及记》《利未记》《民数记》《申命记》,无法被证实全部是摩西所写。
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So by parallel we mean - they're either both spin up remember that's our spin quantum number, that fourth quantum number.
所以我们意味着,它们都是自旋向上,记住我们的自旋量子数，是第四个量子数。
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So if you had some number back in grade school like 123, well, why do we express this as 123?
在小学，像123这样的数，为什么我们要表达成123这样的呢？
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So the temperature is intensive, and you can make intensive properties out of the extensive properties by dividing by the numberof moles in the system.
所以温度是强度量，你可以通过,除以系统中物质的摩尔数,来从广延量中导出强度量。
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Look at line number four, which is so clearly -- simply by looking at this, you can tell it's deficient in the number of syllables.
看第四行，显而易见--单单看一眼,就能看出它的音节数不够。
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And it turns out that simply by counting the number of those spikes that occurs at a period of time.
随后，只要数一数在一定时间内,产生的尖峰脉冲的数量。
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John. -Had John entered, if I've counted correctly, let's pretend I have, John would actually have won this election because John is actually further to the center.
约翰,-让约翰加入,如果我数对了,就当我数对了,约翰将赢得这个选举,因为约翰离中心更近
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It's that the pounds of gold plus the pounds 8 of silver plus the pounds of raisins is no greater than eight.
就是金的磅数加上银的磅数,加上葡萄干的磅数不大于,所以我已经找到了。
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And Pauli says no two electrons in a given system can have the entire set of quantum numbers identical.
而泡利认为在一个给定的系统内,没有两个电子有完全相同的量子数。
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And so when we say something is exponential, we're talking about in terms of the number of bits required to represent it.
所以当我们说某些东西，是指数增长的我们指的,就是代表它的比特数。
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It is joules per atom. Or, if you multiply by Avogadro's number then you will get joules per mole.
焦耳每个原子，或者，如果乘以,阿伏伽德罗常数你会得到焦耳数每摩尔。
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what three quantum numbers tell us, versus what the fourth quantum number can fill in for us in terms of information.
三个量子数和,四个量子数告诉我们的信息。
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If it is, in fact, positive, then we're going to go in here, but now notice what we're doing here.
如果这个数实际上是个正数，那么我们就到,这里面来，但是请注意我们在这做了什么。
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Well, we're talking about a pretty high number here, so to make counting easier, we'll just say 10 lone pairs, because 20 lone pair electrons is the same thing as 10 lone pairs.
好吧，我们这里讨论的是一个挺大的数，为了数起来更容易，我们就说有十对孤对电子，因为二十个跟十对是一个意思。
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4 So even if the correct mathematical answer is 1.4 or whatever, when you divide an int by an int, you only have room in that variable, in the response for an actual integer.
所以即使那个正确的答案是4,或别的数值，当你用一个整型数除以一个整型数，在那个变量的返回值里，只有,存储一个整型数的空间。
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- And then I divide by an int -- that's okay because so long as you have a float involved at some point early on, you're okay.
然后我除以一个整型数-,那是可以的因为现在为止，我们在之前已经,引入了一个浮点数，你是对的。
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Well, here I'm a little bit below 100 and in two, and test one a little bit below 100 as well.
好了我现在在试验2中有一个小于100的数，而实验1也得到了一个小于100的数。
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Let's say you have to go through three or four operations to get a final number, well, do it algebraically.
让我们说,你不得不通过3-4个操作,才能得到最终的数，好吧，用代数方法求解。
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And this spin magnetic quantum number we abbreviate as m sub s, so that's to differentiate from m sub l.
这个自旋磁量子数我们把它简写成ｍ下标ｓ,以和ｍ小标ｌ有所区分。
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He has two electrons here with the same set of quantum numbers. B but these are two separate hydrogen atoms.
因为我写了两个量子数,一样的电子,但这是在两个不同原子中啊。
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And as you might expect, I'm going to then try and see if I can convert that into a float.
正如你希望的我要试着把他们转化为浮点数,等一等。
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OK, great. So, most of you recognize that there are four different possibilities of there's four different electrons that can have those two quantum numbers.
Ｋ，大部分都认为,有４个不同的可能,有四个不同的电子可以有,这两个量子数。
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We started off talking about binary search, and I suggested that this was a log algorithm which it is, which is really kind of nice.
我告诉了你们这是一个对，数级的算法，这是很棒的,我们来一起看看这个算法到底做了什么。
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So if we're talking about the fourth excited state, and we talk instead about principle quantum numbers, what principle quantum number corresponds to the fourth excited state of a hydrogen atom.
如果我们说的是,第四激发态，我们用,主量子数来描述，哪个主量子数对应了,氢原子的第四激发态？
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So I'm first going to look for something that's not in the list, I'm going to see, is minus 1 in this list, so it's going to be at the far end, and if I do that in the basic case, bam.
如果我试试第一种最基本的方法,噢，一下就完成了对不对？,因为这种方法查了下第一个元素，然后发现目标数比较下，因为目标数小于第一个元素。
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And it is equal to the sum of the number of protons plus the number of neutrons.
它等于质子数,加上中子数。
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What you see is that the radius changes with atomic number for constant electron number.
对于等电子数的粒子，离子半径随着,原子数的变化而变化。
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