• So we can actually pop an electron or eject an electron from any single orbital that is occupied within the atom.

    任何一个被占据轨道,打一个电子,或者说发射出一个电子。

    麻省理工公开课 - 化学原理课程节选

  • So what we're saying here is the incident energy, so the energy coming in, is just equal to the minimum energy that's required to eject an electron.

    这里我们来讨论一下,入射能量正好等于,发射出一个电子所需要的最低能量的情况。

    麻省理工公开课 - 化学原理课程节选

  • The electron's going to come out of that highest occupied atomic orbital, that one that's the highest in energy, because that's going to be the at least amount of energy it needs to eject something.

    这个电子应该是从,最高的被占据轨道上来的,它的能级是最高的,因为这样的话发射出它,只需要消耗最少的能量。

    麻省理工公开课 - 化学原理课程节选

  • So that means we're going to need to figure out what is the energy per photon that's emitted by that UV light.

    所以那意味着我们将需要,计算从紫外光源发射出的,每个光子的能量。

    麻省理工公开课 - 化学原理课程节选

  • We're only using up a little bit to eject the electron, then we'll have a lot left over.

    如果我们只需要用很少一部分来发射出电子,那么我们可以得到很多的剩余能量。

    麻省理工公开课 - 化学原理课程节选

  • So we can use an equation to relate the incident energy and the kinetic energy to the ionization energy, or the energy that's required to eject an electron.

    因此我们可以用一个公式将入射能量,与动能和电离能,就是发射出一个电子所需要的能量关联起来。

    麻省理工公开课 - 化学原理课程节选

  • So this means that we can go directly from the energy between two levels to the frequency of the photon that's emitted when you go between those levels.

    这意味着我们可以直接,从两个能级的能量得到它们之间,跃迁发射出光子的频率。

    麻省理工公开课 - 化学原理课程节选

  • And what we have left over is this amount of energy here, which is going to be the kinetic energy of the ejected electron.

    都用来发射它,剩下的这些就是,射电子的动能。

    麻省理工公开课 - 化学原理课程节选

  • So, for example, it's not just the 2 p that we could actually take an electron from, we could also think about ejecting an electron from the 2 s orbital.

    比如,我们不只可以从,2,p,轨道上,打一个电子,还能考虑从,2,s,轨道上,发射出一个电子。

    麻省理工公开课 - 化学原理课程节选

$firstVoiceSent
- 来自原声例句
小调查
请问您想要如何调整此模块?

感谢您的反馈,我们会尽快进行适当修改!
进来说说原因吧 确定
小调查
请问您想要如何调整此模块?

感谢您的反馈,我们会尽快进行适当修改!
进来说说原因吧 确定