• And now we want to find the subset of a that has the maximum value, subject to the weight constraint.

    会有一个值与其对应,现在我们想要找出满足,重量约束条件的a的最大值子集。

    麻省理工公开课 - 计算机科学及编程导论课程节选

  • So I differentiated this object, this is my first derivative and I set it equal to 0 Now in a second I'm going to work with that, but I want to make sure i'm going to find a maximum and not a minimum, so how do I make sure I'm finding a maximum and not a minimum?

    这样我就对它求出导数了,这是一阶导数,令它等于0,一会我们就要计算了,但我先确定一下是最大值还是最小值,我怎么确定是最大值还是最小值呢

    耶鲁公开课 - 博弈论课程节选

  • So, that's sort of the mathematically how we get to a, but we can also just look at the graph here, because every time we go one wavelength we can see that we're back in a maximum.

    这是就我们得到a的数学,办法,但我们可以直接,从图上看,因为每次我们,经过一个波长,都回到一个最大值

    麻省理工公开课 - 化学原理课程节选

  • What we're going to do is, we're asking the question, what is the maximum, choosing S1, of this profit.

    下面我们要问问我们自己,选S1下利润的最大值是多少呢

    耶鲁公开课 - 博弈论课程节选

  • We're going to differentiate with respect to q1, the thing we're trying--our control variable, the thing we're trying to maximize the thing with respect to and set it equal to 0.

    对q1求导,q1是控制变量,也就是我们想要求出的最大值,令它等于0

    耶鲁公开课 - 博弈论课程节选

  • We're asking the question, taking S2 as given, what S1 maximizes this expression and as the gentleman at the back said, I'm going to differentiate and then I'm going to set the thing equal to 0.

    我们来讨论在S2已知的情况下,S1的最大值是多少,就像坐在后排的先生说的那样,我们要去求导然后令导数等于0

    耶鲁公开课 - 博弈论课程节选

  • where the probability of actually finding an electron there mp is going to be your maximum probability.

    电子的概率,达到最大值,我们把它标记成r下标。

    麻省理工公开课 - 化学原理课程节选

  • Find the best response function by differentiating this and maximizing the function for every q2, so we could just... Good, so what we're going to do is, all right good, we're going to... We're trying to maximize.

    求导得出q2取最大值的情况下,参与人1最佳对策是q2的一个函数,说得很好,接下来,我们要求出最大值

    耶鲁公开课 - 博弈论课程节选

  • What I did was I differentiated this fairly simple function with respect to q1 and since I want to find a maximum, what I'm going to do is I'm going to set this thing equal to 0.

    只不过是对q1求导了,既然我们要求出最大值,只需要令导数等于0就可以了

    耶鲁公开课 - 博弈论课程节选

  • The only place q1 appears here is here, so when I differentiate again I'm going to get -2b and sure enough that's negative, which is what I wanted to know, just to check that when I'm finding this thing, I'm finding a maximum and not a minimum.

    只有这一处有q1,因此二阶导数是-2b,它肯定是个负数了,这正是我们想得到的结果,这就验证了我们刚才得出的,是最大值而不是最小值

    耶鲁公开课 - 博弈论课程节选

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