Remember, we don't do a one-to-one correlation, because p x and p y are some linear combination of the m plus 1 and m minus 1 orbital.
记住,我们不需要把它们一一对应,因为px和py轨道是,m等于正负1轨道的线性组合。
The highest probability now is going to be along the x-axis, so that means we're going to have a positive wave function every place where x is positive.
概率最高的地方是沿着x轴,这意味着只要在x,大于零的地方波函数都是正的。
x It says, take the name x and create a binding for that name to the value of the sub-expression and in fact to do this, to stress a point, let's do that.
它的意思是,创建了一个名字,然后创建了对于这个名字,和子表达式的值的绑定,实际上这么做,我们是为了,要强调一个点,让我们来说说这个点。
But he said the energy of an X-Y bond is going to be equal to the square root.
但他说XY键的键能,会等于XX键与YY键键能乘积的平方根。
It's still 1, because you plus plussed the wrong symbol called X. So for now, take-away from this, don't do this.
它还是1,因为你自增的是那个错误的叫做X的符号,现在,拿走这个,不这样做。
It might turn out if I had X-ray vision that what I see is this... Then the answer'd be there's not one train here.
有可能是,我看到的是这样。,答案就不是同一辆火车。
x = 0 plus-- What's the horizontal velocity?
= 0 加上,水平方向的速度是多少
They go back to this formula. If you sold it after five years, then there are twenty-five years left, so 25 x 12 is the number of months left; they plug that into this formula.
如果五年后卖掉房子,他们又搬出公式,此时剩余期限是20五年,所以剩余月份数是25乘以12,把月份数代入这个公式
which is f , divided by the value of the x-axis here.
斜率,而f是p趋于0时pV的极限。
It's like I've got ESP or I'm some character out of the X-Men, Is that what it's called? The X-Men right?
好像我有超能力或者我是X-Men,是叫X-Men吧
If it's in polar form I passed in a radius and angle and I'll compute what the x- and y- value is.
以及半径和角度,但是现在是这样的,不管我是以哪种形式。
OK, as I said, I want equality in the case of points to be, are the x- and y- coordinates the same?
好,正如我所说,我想要这个例子中的,点相等的意思是?
So, it's the x-y plane, you can see there's no electron density anywhere there.
它在xy平面,你们可以看到在这里没有电子密度。
But for now let's simply say that we have a diffraction which we know occurs only by wave-like behavior and it involves the use of x-rays. Why x-rays?
但现在让我们来简单假设一下,我们知道,只波才发生衍射,而且衍射涉及了X光的使用,为什么是X光?
So the normal--the bell-shaped curve in that case for the x/n is going to look something like this.
那么x/n的钟形曲线,大概就会是这个样子
OK? And in fact, if you look at the code up here, and it's on your handout, the very first one, x 1, right here- if I could ask you to look at it-- is a piece of code to do it. And I'm less interested in the code than how we're going to analyze it, but let's look at it for a second.
实际上,如果你看看,你们课堂发的材料上面的代码,第一页上的,就是那-,大家请看看实现的这一部分代码,我不太关心,我们会怎么解释这个代码,首先让我们先看看。
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