And, I know I need to come up with four symmetric equi-length bonds, and let's just see, let's draw the structure here.
我想我们需要,4个对称的等长的键,让我们画出CH4的结构。
Now, it's not going to be symmetric is it, because there's two fluorines and two chlorines.
现在,它将不会对称,因为有两个氟原子和两个氯原子。
And let's also make our egg perfectly symmetric and perfectly round.
而且我们要把蛋想成是,完全对称完全圆的。
There's no particular reason why games have to be symmetric.
博弈未必都是对称的
Most restriction enzyme also recognize symmetric sequences of DNA, GAATTC for example.
大多数限制性内切酶,也能识别DNA的对称序列,例如GAATTC
We somehow have to take hydrogen, attach it to carbon, and we have to make it symmetric, and we have to make it nonpolar.
我们需要把H接到C周围,而且我们需要让它是对称,且非极性的。
And yet, the molecule is symmetric and nonpolar.
所以这个分子是对称非极性的。
If it's symmetric, that means that each bond has exactly the same energy.
这意味着如果他们对称,那么每根键的能量是一样的。
Symmetric disposition of polar bonds still results in a nonpolar molecule.
空间对称的极性键分布,还是会导致整个分子为非极性分子。
If we can do that, we'll end up with a symmetric nonpolar molecule.
如果我们能这样做,我们就能得到那些对称非极性的分子。
But, we also know that it's symmetric.
而且非常对称。
And, it's going to be symmetric.
现在是对称的了。
Right, it's symmetric.
是的,对称。
Can everyone see that is symmetric?
每个人都可以看出这他们是对称的
The thing is still not dominated and we could still have done exactly the same analysis, and actually you can see I'm not very far off in the numbers I made up, but things are not perfectly symmetric.
这虽然不能成为劣势策略,但我们还是能得出一样的分析结果,实际上这和我编的数字相差也不是很远,凡事并不总是绝对对称的嘛
This bond is polar, but again, as I alluded to earlier, because the carbon is centered in the tetrahedron, because of the sp3 hybridization, the molecule itself is symmetric and nonpolar.
这个键是非极性的,但是,我们断言过早,因为C是中心原子,由于sp3杂化,这个分子本身是非极性的且对称的。
It makes sense to draw the wave function as a circle, because we do know that 1 s orbitals are spherically symmetric.
把波函数画成一个圆是有道理的,因为我们知道1s轨道是球对称的。
The graph to the left, this is the s orbital, symmetric.
在左边的图是对称的S轨道,对称的。
Actually, we can do it a little better than that, since we know the game is symmetric, we know that S1* is actually equal to S2*.
实际上我们能得出更多,因为我们知道这个博弈是对称的,我们知道S1*=S2
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