OK, so w, first of all, work is being done to the system on the left hand side here.
好的,首先,我们通过左边对系统做功。
So w, the work is less for the irreversible process than the reversible process.
不可逆过程中系统对外界,做的功要比可逆过程时小。
I did, that's ok. -So...okay ? So Kennedy, Reagan, Clinton, or George W. who?
没关系啦,-好吧,那到底是肯尼迪,里根,克林顿,还是布什?
So a will be negative and w, in fact, will be less than mg.
那么 a 就会变负,w 事实上就会比 mg 小
So we can just write out what those are, minus w prime over q1 prime q1 is greater than minus w over q1.
因此可以写出,负w一撇除以q1一撇,大于负w除以。
w=p1v1 So we write down p1, V1.
我们写下。
So w over q1 prime is greater than minus w over q1.
因此w除以q1一撇大于负w除以q1,等于。
w So w irreversible is bigger than w reversible.
因此不可逆的w大于可逆的。
Wrev So minus w reversible, 1 p2 is less than p1, so p2 over p1 is less than one, log of something less than 1 is negative times negative.
那么,而p2小于p1,p2/p1小于,取对数后是负数,负负得正。
q2 So it's got q2, w and it's got a cycle w.
得到的热量是,有一个循环,功是。
U OK, so let's look at delta u. Delta u is q plus w.
好的,让我们看看Δ
Q So it's just capital W over capital Q, q1 which is to say it's minus all that stuff over q1.
所以效率就是W除以,等于负的所有这些之和除以。
w So that means that minus w prime must equal w And w is greater than zero.
也就是说负w一撇等于,在这之中。
So it's the same as q reversible plus w reversible.
它们是相等的,因此这也等于q可逆加w可逆。
And of course, in either case, w delta u is q plus w, so it's q irreversible plus w irreversible, u being a state function it's the same in either case.
当然了,在这两个过程中,Δu都等于q加,因此现在是q不可逆加w不可逆,同时u在这两个过程中都是态函数。
U It's u, because u is to q plus w right, heat and work, but it's adiabatic. So there's no heat, exchange with the environment, and it's constant volume, so there's no p dV work, right.
什么是零?是U,因为,等于q加w,热量和功,但这是绝热的,所以系统与环境间没有热量交换;,同时它是灯体的,所以也没有pdV形式的功。
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