a I'm not, so come down here check palindrome that the two end points a and a are the same and call this again also.
判断两端都是,然后再次调用,注意发生了什么。
OK, as I said, I want equality in the case of points to be, are the x- and y- coordinates the same?
好,正如我所说,我想要这个例子中的,点相等的意思是?
And, if you laid this out in a table, as Mendeleev did with his cards, you would find that the local maxima all occur roughly in the same horizontal position from the end points of the rows.
如果你们这些放到一张表格上去,像是门捷列夫用纸牌做的那样,你会发现局部的最高点,会出现在同一个水平高度,从这些行的最后一点。
For you or for me, it is not a challenge to walk around these cubes, or the audience or somebody from different points of view and recognize that they are really the same person.
对于我们这样的人,换个角度绕场行走,围着某个观众或者其他人去走,会认识到他们是同一个人。
Now, y points to the same place as X. So, wait now y is fixed.
现在,y和x指向同一东西,所以现在y被修正了。
There's the base case. If it's longer than one, what do I want to do? Well I'd like to check the two end points to see are they the same character? And if they are, then oh, I just need to know is everything else in the middle a palindrome?
如果只有一个元素也是回文,这是基本事件,如果比一个长的话那么我应该怎么做?,我将会查看两头是否相同?,如果是的,我只要知道中间剩下的部分是不是回文即可?
Can you fix it so that y points to the same pointee as X?
你能使y指向x所指向的数据么?
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