• And the way I remember that is I put a little cross here, and then I make that the plus end.

    我还记得要,在箭头尾部打个叉,然后让加法完结了。

    麻省理工公开课 - 固态化学导论课程节选

  • We do in fact--I do have conversations with all 30 plus of the teaching fellows about all 300 plus of the students at the end of the semester, and that is in the end what determines the outcome.

    事实上,我们----在这个学期末,为了了解这300多个同学的情况,我会和30多个助教谈话,这最终帮助决定成绩。

    哈佛公开课 - 计算机科学课程节选

  • And then we end up having 6 shared electrons, 2 from each of the bonds, so we end up with a formal charge on sulfur of plus 1.

    然后我们有六个共用电子,每个键两个,因此最终硫的形式电荷量为正一。

    麻省理工公开课 - 化学原理课程节选

  • That is to say I can now reroute that sodium plus chlorine reaction and go a different way, but I still end up with the same change in energy.

    也就是说,我可以重新定义一种,钠与氯的反应途径,从另一种途径来实现反应,但是能量的变化过程相同。

    麻省理工公开课 - 固态化学导论课程节选

  • If we look at our last structure here where we have nitrogen the middle, we can also figure out all those formal charges, and in this case we have plus 1 on the nitrogen, we have minus 2 on the carbon, and then we end up with a 0 on the sulfur there.

    如果我们来看看最后一个结构,在中间的原子是氮,我们同样可以计算出所有的形式电荷,而在这种情况下,氮为正一,碳为负二,而最后硫为零。

    麻省理工公开课 - 化学原理课程节选

  • The highest occupied orbital is now the 2 s orbital, 1 s 2 2 s 1 so we're going to end up with boron 2 plus 1 s 2, 2 s 1, plus the electron coming out of there.

    现在最高的被占据轨道是,2,s,轨道,因此结果应该是正二价的硼,再加上一个出射的电子。

    麻省理工公开课 - 化学原理课程节选

  • So what we'll end up with is boron plus, 1 s 2 2 s 2 1 s 2, 2 s 2, E and what we say is the delta energy or the change in energy as the same thing as saying the energy of the products minus the energy of our reactant here, that's how much energy we have to put into the system to eject an electron.

    所以结果应该是正一价的硼,电子排布为,我们说,Δ,也就是,E,的变化量,等于生成物的能量,减去反应物的能量,这就是我们从这个系统中,打出一个电子所需要的能量。

    麻省理工公开课 - 化学原理课程节选

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