RT2 So it's R T2, right, now we're at a lower temperature times log the log of V4 over V3.
等于,这时温度比刚才低,乘以。
And then we can take the derivative with respect to temperature, it's just R over molar volume minus b.
这样我们求,压强对温度的偏导数,结果等于R除以摩尔体积V杠减去b的差。
Over here, we have dq=Cp dT, the heat, the proportionality between heat - and temperature rise is given by this, the constant pressure heat capacity.
这里我有dq=CpdT,这是热量,这是联系热量,和温度变化的系数,恒压热容。
Now if you're at the temperature which is b higher than the inversion temperature, in that case here, a over RT is small compared to b, and this is going to turn out to be negative.
T>Tinv】,这时a/bR小于,结果是负数,因此如果温度。
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