V So this nR over V. And then, using the relation again, T we can just write this as p over T.
恒定温度下的dp/dT等于nR除以,再次利用状态方程,可以把它写成p除以。
p So dV/dT at constant pressure is just nR over p.
所以恒定压强下dV/dT等于nR除以。
All right. So we have that square root NR.
好,看看这个NR求平方根方法。
It's nR log of p2 over p1 for the process where there's a pressure change.
结果是dS等于nR乘以p2除以p1的对数,这是对压强变化的结果。
So it's nR integral from V1 to V2 dV over V.
即nR除以V乘以dV从V1到V2的积分。
So it's nR log V2 over V1.
结果是nR乘以V2除以V1的对数。
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