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• It is joules per atom. Or, if you multiply by Avogadro's number then you will get joules per mole.

焦耳每个原子，或者，如果乘以,阿伏伽德罗常数你会得到焦耳数每摩尔。

麻省理工公开课 - 固态化学导论课程节选

• 475 Multiply by 1.7475 787kJ/mol and you end up with minus 787 kilojoules per mole.

乘以1。,最终得到。

麻省理工公开课 - 固态化学导论课程节选

• How do we do that correction? When I first tried this, I thought, fine I'll multiply by 365/60, but I forgot this is a leap year.

那么怎么换算呢,我第一次试的时候,我想,我乘以365/60,但是我忘了,今年是闰年

耶鲁公开课 - 金融市场课程节选

• And in the even case, I'd square, divide by half, call this again: in the odd case, I go b minus 1 and then multiply by a.

就直接求a的平方的二分之b次方，如果是奇数的话，就去求a的b-1次方乘以a，以此递归下去。

麻省理工公开课 - 计算机科学及编程导论课程节选

• But remember that we need to multiply it by the volume here, the volume of some sphere we've defined.

但记住我们需要把它乘以体积，乘以一个我们定义的壳层的体积。

麻省理工公开课 - 化学原理课程节选

• You've got to juggle the two equations, multiply that by 4, multiply that by 3, add and subtract and so on.

同时处理这两个方程,这个两边乘以4,另一个两边乘以3,将两方程相加或相减求出答案

耶鲁公开课 - 基础物理课程节选

• Well, Fahrenheit came along and thought, well, you know, 7-1/2, that's kind of silly; 22-1/2 that's, kind of silly So let's multiply everything by four.

然后华伦海特来了，他想，7。5，听起来有些犯傻;,22。5，那也够傻的,我们还是把所有的东西乘以四吧。

麻省理工公开课 - 热力学与动力学课程节选

• Can I multiply the ? by the 4 just to save myself some time?

我先算?乘以4吧,这样省事儿

耶鲁公开课 - 博弈论课程节选

• Take your own weight in your mind and multiply it by three.

想一下你们自己的体重,然后再乘以三

耶鲁公开课 - 关于食物的心理学、生物学和政治学课程节选

• That's true, but especially because of my parenthesization 32 over here, because I'm saying, "Do f minus 32, but then multiply it by the division on the left."

是那样的，但是特别地，因为我这里加上了括号,因为我指明，“f减去，然后它乘以左边的那个除法的结果“

哈佛公开课 - 计算机科学课程节选

• What I am going to do now is I am going to multiply by N Avogadro and then add Born repulsion.

我接下来要做的是,将其乘以阿伏加德罗常数,再加入Born的排斥作用。

麻省理工公开课 - 固态化学导论课程节选

• So, once we figure out what our probability of backscattering is, we'll just raise that to the 1/2, and we'll multiply that by 12 . 20 centimeters.

所以一旦我们,知道了散射概率，我们开根号。

麻省理工公开课 - 化学原理课程节选

• But I know when I multiply a vector by a number, I get a vector in the same direction.

但是我所知道的是当矢量乘以一个常数,我会得到一个同方向的矢量

耶鲁公开课 - 基础物理课程节选

• So if we want to talk about the volume of that, we just talk about the surface area, which is 4 pi r squared, and we multiply that by the thickness d r.

如果我们要讨论它的体积，我们要用的是表面面积，也就是４πｒ的平方，乘以厚度ｄｒ

麻省理工公开课 - 化学原理课程节选

• You see the difference in electronegativity, square it, multiply it by one-quarter and raise that to the power e.

你看到了电负性的差异，开方，乘以四分之一,在移到e上去做指数。

麻省理工公开课 - 固态化学导论课程节选

• I am only counting in one direction, 2 so I have to multiply this whole thing by two because I have to count both directions.

因为我只是在一个方向上计数，所以我要把这些所有乘以,因为我们必须考虑到2个方向。

麻省理工公开课 - 固态化学导论课程节选

• Multiply a by a to the b minus 1.

这很不错对不对？

麻省理工公开课 - 计算机科学及编程导论课程节选

• Subtract that from one, 100 multiply it by 100 and you have something between zero and 100.

用一减去后面那部分，再整体乘以,你就能得到0-100间的一些数值。

麻省理工公开课 - 固态化学导论课程节选

• And what I am going to do is say start with this ion, add up the energy associated with the interactions between that ion and everybody else in the row and then multiply it by Avogadro's number, because that is the number of atoms there are in a row.

接下来我要从这一离子开始，加上相互作用的能量，也就是这一离子,和其它所有在这一行的离子之间的能量,再乘以阿伏加德罗常数，因为这是在一行的原子的数量。

麻省理工公开课 - 固态化学导论课程节选

• Once you've got that, you can do minus 7 times a vector Just take the vector, multiply it by Pi and flip it over.

明白这点之后,你就可以计算-7乘以矢量,只需用 π 去乘以那个矢量,然后将其方向调转

耶鲁公开课 - 基础物理课程节选

• And then for some reason, that nobody understands, 16/15 he decided to multiply again by 16/15, and that's how we get 32 for freezing of water and 96 in his words for the temperature in the mouth or underneath armpit of a living man in good health.

然后，因为同样的原因，没人搞得明白，他决定再乘以，现在水的冰点变成了32度,而96度，拿他的话来说,是健康状况良好的人,口腔或腋窝的温度。

麻省理工公开课 - 热力学与动力学课程节选

• So if we take this term, which is a volume term, and multiply it by probability over volume, what we're going to end up with is an actual probability of finding our electron at that distance, r, from the nucleus.

如果我们取这项，也就是体积项然后，乘以概率除以体积，我们能得到的就是真正在距离,原子核ｒ处找到电子的概率。

麻省理工公开课 - 化学原理课程节选

• What Einstein then clarified for us was that we could also be talking about energies, and he described the relationship between frequency and energy that they're proportional, if you want to know the energy, you just multiply the frequency by Planck's constant.

爱因斯坦阐述的是我们,也可以从能量的角度来谈论，他描述频率和能量之间的关系,是成比例的，如果希望知道能量值，你用普朗克常数乘以频率就可以了。

麻省理工公开课 - 化学原理课程节选

• Instead of summing them and dividing by M, I multiply them all together and take the nth root of them.

我把所有的乘在一起然后开n次方,而不是把他们加总再除以个数

耶鲁公开课 - 金融市场课程节选

• So if we actually go ahead and multiply it by the volume of our shell, then we end up just with probability, which is kind of a nicer term to be thinking about here.

乘以壳层的体积,我们就得到了概率，在这里从这个角度，理解问题更好一些,如果我们考虑的是。

麻省理工公开课 - 化学原理课程节选

• Then it's very clear the way you patch it up is you multiply it by this constant and now we're all set.

很明显,弥补的方法就是,乘以这个常数就全部搞定了

耶鲁公开课 - 基础物理课程节选

• The beauty of that is now we have discovered a notion of what it means to multiply a vector by a number.

现在最美妙的就是我们就已经知道,数字乘以矢量的意义

耶鲁公开课 - 基础物理课程节选

• You can take this vector, multiply it by one number, take that vector, multiply it by another number, add the two of them.

比如将这个矢量,乘上一个数,然后将另一个矢量,乘上另外一个数,把这两个矢量相加

耶鲁公开课 - 基础物理课程节选

• If you multiply it by 2, you get a vector two times as long.

如果拿它乘以2,你就得到一个两倍长的矢量

耶鲁公开课 - 基础物理课程节选

• So, what we can do to actually get a probability instead of a probability density that we're talking about is to take the wave function squared, which we know is probability density, and multiply it by the volume of that very, very thin spherical shell that we're talking about at distance r.

我们能得到一个概率,而不是概率密度的方法,就是取波函数的平方，也就是概率密度，然后把它乘以一个在ｒ处的,非常非常小的,壳层体积。

麻省理工公开课 - 化学原理课程节选

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