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So what we're going to do is set these two things equal to each other, put in stars here.
我们只需要令这两个表达式相等,在这里标注上*号
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I've set these two things equal to each other: I've got one equation and one unknown.
我让两个方程相等,只剩下了一个等式和一个未知数
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First let's set the external pressure equal to zero.
首先，让外部压强为零。
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First one says, if you knew the force acting on any body, without going into what caused the force, then you may set that force equal the mass times acceleration of the body.
第一部分是,如果你知道作用在任一物体上的力,无论这个力的来源是什么,都可以令力等于质量乘以物体的加速度
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It's gonna hold integers so I have to say int as we'll see 0 and set it equal to 0.
因为需要是整数，所以我们把它定义为int类型,并初始化为。
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At my maximum, I'll put a hat over it to indicate this is the argmax; at my maximum I'm going to set this thing equal to 0.
给每个最大值都标注上一个帽来,在最大值处导数方程等于0
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Set the intersection points equal, the equations equal to each other and solve.
令交点处的两个方程相等,然后就可以解出来了
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You set price below his but above or equal to cost.
你定价比他低但是大于或等于成本
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p2 I'm going to set that equal to p2.
现在外界压强为。
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Good, take a derivative and Set it equal to zero.
好的,求导,然后呢,令它等于0
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And then set it equal to 0.
还要令导数等于0
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So basically what I'm going to do here is I'm going to set my price to equal his price, minus a little bit, I'll just undercut him a little bit and by just undercutting him a little bit, I'm going to get the whole of the market and I'll make as much money as I can on those sales.
所以基本上我要做的是,设定我的价格等于他的价格,减去一点点,我的价格将仅仅比他的低一点点,并且通过比他的价格低一点点,我将占领整个市场,那些销售带给我尽可能多的钱
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So I differentiated this object, this is my first derivative and I set it equal to 0 Now in a second I'm going to work with that, but I want to make sure i'm going to find a maximum and not a minimum, so how do I make sure I'm finding a maximum and not a minimum?
这样我就对它求出导数了,这是一阶导数,令它等于0,一会我们就要计算了,但我先确定一下是最大值还是最小值,我怎么确定是最大值还是最小值呢
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p2 and let's set p external equal to p2.
让外部的p等于。
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At C okay, so the Nash Equilibrium here, the Nash Equilibrium is for both firms to set their prices equal to marginal cost.
价格定在C,好的,所以这里的纳什均衡,纳什均衡是两家公司都把它们的价格,设定在边际成本
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We're going to differentiate with respect to q1, the thing we're trying--our control variable, the thing we're trying to maximize the thing with respect to and set it equal to 0.
对q1求导,q1是控制变量,也就是我们想要求出的最大值,令它等于0
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We're asking the question, taking S2 as given, what S1 maximizes this expression and as the gentleman at the back said, I'm going to differentiate and then I'm going to set the thing equal to 0.
我们来讨论在S2已知的情况下,S1的最大值是多少,就像坐在后排的先生说的那样,我们要去求导然后令导数等于0
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What I did was I differentiated this fairly simple function with respect to q1 and since I want to find a maximum, what I'm going to do is I'm going to set this thing equal to 0.
只不过是对q1求导了,既然我们要求出最大值,只需要令导数等于0就可以了
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If Firm II is charging C, Then a best response for Firm 1 is to set price equal to marginal costs, and if Firm 1 is pricing at marginal cost, then conversely a best response for Firm 2 is to price at marginal cost.
如果公司2选择了C,公司1的最佳对策是,定价在边际成本,如果公司1定价在边际成本,同样的,公司2的最佳对策,也是定价在边际成本
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So what we're going to do is take the equations for those two lines, so here's one of those equations and here's the other one, set the P in those equations equal to X, I've got two equations in one unknown, I'm sorry, I've got one equation and one unknown.
接下来我们只需要,列出这两条线各自的方程,也就是这个方程和这个方程,把方程中的P换成X,我就得到了两个等式和一个未知数,错了,是一个等式和一个未知数
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It's reasonable because it's meant TMP for temporary purposes just to call it temp or T-M-P for short, X and I can define temp as -- why don't I set it as equal to X, initially, because now that I've stored X in a separate chunk of memory, I can now change its value and then I can say Y gets, not X, but temp, and so now I've actually swapped these values.
这是合理的，因为它是为,暂时的目的，只要叫它Temp或简称它为，我可以定义temp为--为什么我不把它设定为等于，最初的，因为现在我把X存储在一个单独的内存块中,我现在可以改变它的值，然后我说Y等于，不是X，而是temp，所以现在我交换这些值。
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