So in other words, every time I merge the point that I kept emphasizing verbally there and that I'm only touching each number once, means that we have to account for the amount of time it takes to merge N which is going to be just N. Now, this is again one of these cyclical answers.

换言之，之前在做合并时,我不停地强调,对每个数字我只碰了一次，这就是说,我们要记录合并所花的时间量,也就是这里的,这又是一种循环性的答案。

哈佛公开课 - 计算机科学课程节选

Now, it's kind of a cyclical argument here because how do you sort the left half of N elements?

在这儿有点循环的意思,那么如何对N个元素中的左半部分进行排序呢？

哈佛公开课 - 计算机科学课程节选

It's not a cyclical and useless definition.

这不是一个循环式的,没有意义的定义

耶鲁公开课 - 基础物理课程节选

Really there's no work to be done if I am handed all in sorted order so, you know, There's no work to be done if I'm handed all of the arrays in sorted order so, you know, if I demand that you give me this assumption that the cups are already sorted and then I'll sort them for you, I mean, this is kind of a cyclical argument.

如果杯子是有序排列的,那就没必要再对它进行排序了，同样如果给出的序列本身就是有序的,那也不必再做什么，如果给出这样的假设：,杯子已经有序，但仍需要对其进行排序，这像是个循环的论点。

哈佛公开课 - 计算机科学课程节选