But if you keep on doing boxes within boxes, I'm going to converge in on that intersection.

如果你不断缩小方格,最后就会只剩交点了

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So what we're going to converge in on to, is the S1*, let's call it in this case, is equal to 1 plus B S2* and that S2* is equal to 1 plus B S1*.

交点的横坐标是S1,暂且这么叫吧,S1*=1+BS2*,而S2*=1+BS1

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