Well, oxygen, we'll put a hydrogen here, 1 2 3 4 hydrogen here, and one, two, three, four.
如果把一个氢放在这边,另一个氢这边,然后。
And the thing you should notice here is that it's doing a lot of the same things over 2 1 and over again. So, for example, we'll see 2, 1 2 1 here. And 2, 1 here.
在这里你要注意的是,它不断在重复同样的工作,例如我们看这里的1,还有这里的。
We'll call them 1, 2, 3, 4, 5, 6, 7, 8, 9, and 10.
1 2 3 4 5 6 7 8 9 10
1 2 3 Let's now do negative one, two, three.
让我们先在试。
And so, for today, for example, it says Classification Schemes, Mendeleev, Atomic Structure, A Readings Chapter 1, Chapter 2, Appendix A.
今天,举个例子,讲的是分类法,门捷列夫,原子结构,阅读第1,第2章,和附录。
And if we put that in our bond here, we have 1, 2, 3 bonds, plus we have one lone pair left over.
如果我们把它们放到键里,我们有1,2,3个键,还剩下一对孤对在这里。
And the Former Prophets include the books of Joshua, Judges, 1 and 2 Samuel, 1 and 2 Kings. They read as a historical narrative.
前先知书》包括《约书亚书》《士师记》,《撒母尔书1-2》《列王记1-2》它们被当作史料。
Then if you fast forward to 2005 and look at the average return that was posted for 2000,it was +1.2%.
如果把时间快进至2005,5年后公报的2000年平均收益,变成了1.2%
Well, Fahrenheit came along and thought, well, you know, 7-1/2, that's kind of silly; 22-1/2 that's, kind of silly So let's multiply everything by four.
然后华伦海特来了,他想,7。5,听起来有些犯傻;,22。5,那也够傻的,我们还是把所有的东西乘以四吧。
So if you put 1 and 2 together you can get only changing things could be destroyed.
把1和2放在一块儿就可以得出,只有能改变的东西能毁灭。
6 Well again, we can go to our ones column, twos, four, eight, 16, 2 damn, 32. So we can go to 32 128 and then we can go to 64, and then 128, 1 2 3 4 5 6 7 8 and this gives me 1, 2, 3, 4, 5, 6, 7, 8.
好吧,再一次回到一位,二位,四位,八位,该死的,32,等等,所以我们可以找到32位2,再64,然后,那么我们就有了。
So kind of that strange cursive r, and our n final is 2, R so 1 over 2 squared minus n initial, so 1 over 3 squared.
因为我们可以在这里用到它,这个有点奇怪的花体。
And frankly it would be incredibly time-consuming and tedious for me, to count this room full of people old school style-- 1, 2, 3 and so forth.
坦白说,按学校的老办法一个人一个人的数,1个,2个,3个……,对我来说极其费时费力。
So what is this? This is Player 2's best response, so Player 1's best response to Player 2 producing half monopoly output.
这是什么,这是参与人2的最佳对策,即参与人1对于2半垄断产量的最佳对策
/2 So the bond order is going to be equal to 1/2, and then it will be 2 minus 2.
它的键序等于,然后乘以2减去2。
Periodic Table, Table of Constants, and you are allowed an aid sheet, an 8-1/2 by 11 sheet of paper.
元素周期表,常数表,你允许带帮助表格,一个8-1/2乘11的纸。
应用推荐