• The experts at N.I.H.say you may have to repeat this process a few times.

    VOA: special.2010.03.31

  • So notice a difference in these structures, is this has an n h bond whereas this has an o h bond.

    注意它们之间的有一点不同,那就是一个有氮氢键,而另一个有氧氢键。

    麻省理工公开课 - 化学原理课程节选

  • So, why don't you go ahead and tell me, keeping that in mind, which atom in terms of h c or n would you expect to be in the center of hydrogen cyanide?

    那么,请大家来告诉我,并且记住它,你认为氢,碳和氮中哪个原子,应该在氰化氢的中间呢?

    麻省理工公开课 - 化学原理课程节选

  • The traditional spelling is d-o-u-g-h-n-u-t but people often just spell it d-o-n-u-t.

    VOA: special.2010.04.12

  • Why didn't they keep right on going with G, H, I, J, K, L, M, N, O, P?

    为什么他们不接着写下去呢,按照字母表

    耶鲁公开课 - 聆听音乐课程节选

  • Doctor Anthony Fauci at N.I.H.called the findings an important step forward.

    VOA: special.2009.09.30

  • Bohr said that the angular momentum, mvr where n is this integer counter h over 2 pi.

    波尔提及到角动量,是被量化了的,mvr,is,quantized,这里的n等于一个整数乘以h除以2π

    麻省理工公开课 - 固态化学导论课程节选

  • And that in the case of constant volume, U in this case that's my delta u, and then I'll H add my little delta n term to get delta H.

    这是在等体情形下,此时的到的是Δ,然后我可以加上Δn的项来得到Δ

    麻省理工公开课 - 热力学与动力学课程节选

  • And if you put this in the well-ventilated area, if you prepare this outside, the h c n gas will actually be released into the air, so you're safe, you can eat it later.

    而如果你把它们放在通风良好的地方,在室外处理,那么氰化氢气体,将会被释放到空气中,这样你就安全了,过后就可以吃了。

    麻省理工公开课 - 化学原理课程节选

  • So, for example, down here I wrote that it was n 2 and that it was h 2, but when I re-wrote the molecules up here, you saw that it's an h h single bond where it's a nitrogen-nitrogen triple bond.

    比如,在这下面我写的是氮分子2,而这个是氢分子,但我在上面把这些分子的形式改写了,大家可以看到,这是一个氢与氢之间的单键,含一个氮与氮之间的三键。

    麻省理工公开课 - 化学原理课程节选

  • The other thing is that we can re-write our h c n in terms of bonds.

    还有一件事是我们可以用键的形式来表示氰化氢。

    麻省理工公开课 - 化学原理课程节选

  • So it looks a lot less messy if we just draw our Lewis structure like this for h c n, where we have h bonded to c triple bonded to n, and then a lone pair on the nitrogen there.

    这看起来整洁了不少,如果我们把氰化氢的路易斯结构画成这样的话,这样我们就有氢与碳之间的单键和碳与氮之间三键,然后还有一对孤对电子在氮这里。

    麻省理工公开课 - 化学原理课程节选

  • So instead of being equal to negative z squared, now we're equal to negative z effective squared times r h all over n squared.

    这里不再等于-z的平方,现在我们等于-有效的z的平方,乘以RH除以n的平方。

    麻省理工公开课 - 化学原理课程节选

  • So we have h c n.

    那么我们有氢,碳和氮。

    麻省理工公开课 - 化学原理课程节选

  • So, the first thing we do is put two electrons between h and c, and then two electrons between c and n.

    那么,我们先在氢和碳之间放两个电子,然后在碳和氮之间再放两个电子。

    麻省理工公开课 - 化学原理课程节选

  • So our skeleton tells us that carbon is in the middle, so we'll put the h on one side, and the n on the other side there.

    我们的骨架告诉我们碳原子应该放在中间,因此我们把氢原子放在一边,把氮原子放在另外一边。

    麻省理工公开课 - 化学原理课程节选

  • And that's going to be equal to negative z effective squared times r h over n squared.

    有效的z的平方,乘以RH除以n的平方。

    麻省理工公开课 - 化学原理课程节选

  • And the last thing we can think about is how do we name this n h bond, and again, we just name it based on it symmetry.

    最后我们要讨论的是,如何命名这个NH键,同样,我们基于它的对称性命名它。

    麻省理工公开课 - 化学原理课程节选

  • So we know that we can relate to z effective to the actual energy level of each of those orbitals, and we can do that using this equation here where it's negative z effective squared r h over n squared, we're going to see that again and again.

    我们知道我们可以将有效电荷量与,每个轨道的实际能级联系起来,我们可以使用方程去解它,乘以RH除以n的平方,它等于负的有效电荷量的平方,我们将会一次又一次的看到它。

    麻省理工公开课 - 化学原理课程节选

  • So the square root of n squared r e over r h.

    这里的n值是什么呢?

    麻省理工公开课 - 化学原理课程节选

  • So, we can get from these energy differences to frequency h by frequency is equal to r sub h over Planck's constant 1 times 1 over n final squared minus 1 over n initial squared.

    所以我们通过不同能量,得到不同频率,频率等于R下标,除以普朗克常数乘以1除以n末的平方减去。

    麻省理工公开课 - 化学原理课程节选

  • We also know how to figure out the energy of this orbital, and we know how to figure out the energy using this formula here, which was the binding energy, -Rh which is negative r h, we can plug it in because n equals 1, so over 1 squared, and the actual energy is here.

    我们知道如何算出,这个轨道的能级,而且我们知道如何,用这个公式,算出能量,也即是结合能,等于,我们把n等于1代进来,所以除以1的平方,这就是能量。

    麻省理工公开课 - 化学原理课程节选

  • So if we do this and we form the molecule ammonia, let's switch to a clicker question, and have you tell me what the bond angle - is going to be in ammonia -- HNH Actually, let me draw it on the board as you look -- actually, can you put the class notes on, since you don't actually have your notes to refer to.

    如果这样做的话,我们就可以形成氨分子,让我们来做一个课堂练习,你们告诉我氨分子中的键角是多少-,键角,the,hnh,bond,angle。,实际上让我在黑板上画出它来,这样你们可以看到实际上-,你能把课堂讲义放出来吗,因为你们没有讲义可以参考。

    麻省理工公开课 - 化学原理课程节选

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