• So you see in the hybrid orbital we actually have a larger lobe on top where they constructively interfered.

    所以你们可以看到在杂化轨道里,我们上面,由很大的一叶相长干涉。

    麻省理工公开课 - 化学原理课程节选

  • So that leaves each carbon with only one hybrid orbital left.

    这样每个碳原子只剩下一个杂化轨道。

    麻省理工公开课 - 化学原理课程节选

  • So if you picture this as our s p 2 carbon atom where we have three hybrid orbitals, and then one p y orbital coming right out at us.

    如果你把这想象成sp2碳原子,这里有3个杂化轨道,然后一个py轨道朝向我们。

    麻省理工公开课 - 化学原理课程节选

  • And if we think about the six hydrogens, now each of those are going to bind by combining one of the carbon hybrid orbitals to a 1 s orbital of hydrogen.

    如果我们考虑有六个氢原子,每个都会合起来,碳杂化轨道成键,每个氢的1s轨道。

    麻省理工公开课 - 化学原理课程节选

  • So this is a little bit trickier to look at and see what it means, but essentially we have two hybrid orbitals, which are shown in blue here, and then we have one p orbital that's left alone that's going up and down on the page.

    看这个图肯能会觉得比较诡异,但本质上,骂我们有两个杂化轨道,这里用蓝色表示,还有剩下一个p轨道,在图中上下方向上。

    麻省理工公开课 - 化学原理课程节选

  • And hybrid orbitals are all going to be completely equal, and lower in energy than the p orbital.

    杂化轨道是完全相等的,你会注意到它们的能量比s轨道高,比p轨道低。

    麻省理工公开课 - 化学原理课程节选

  • All right, so if we think about b h bond here, again, it's the sigma bond, and we're going to say it's a boron 2 s p 2 hybrid orbital interacting with a hydrogen 1 s orbital.

    这可以告诉我们,为什么它倾向于周围只有6个电子,好了,考虑一下这里的BH键,同样的,它是sigma键,我们说。

    麻省理工公开课 - 化学原理课程节选

  • The reason that it's a sigma bond is sp3 because the s p 3 hybrid orbital is directly interacting with the 1 s orbital of the hydrogen atom, and that's going to happen on the internuclear axis, they're just coming together.

    它是sigma键的原因,是因为,杂化轨道直接和氢原子1s轨道相互作用,它们作用发生在核间轴上,它们会到一起。

    麻省理工公开课 - 化学原理课程节选

  • So it's along the bond axis and it's between a carbon s p 2 hybrid, and then the hydrogen is just a 1 s orbital that we're combining here.

    所以它是沿着键轴方向的,而且这里是一个碳sp2杂化轨道,和一个氢的1s轨道的结合,在这里我们可以合并他们。

    麻省理工公开课 - 化学原理课程节选

  • So we end up with 1 p orbital completely untouched, and three hybrid s p 2 orbitals.

    没有变化,所以我们得到的是1个完全没有变化p轨道。

    麻省理工公开课 - 化学原理课程节选

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