• The threshold is called theta.

    称为theta

    youdao

  • theta, y=1, else y=0.

    当 a >=thetay=1,反之 y=0

    youdao

  • So there's no restriction on theta.

    在θ没有限制

    youdao

  • With the chain rule, gives me a theta dot.

    根据链式法则得到θ

    youdao

  • Notice it's no longer even a function of theta.

    注意不再是,关于θ函数

    youdao

  • But, we have the constraint, a equals b cosine theta.

    但是我们约束条件a=b*cosθ

    youdao

  • R Now, v equals omega R, R so that equals theta dot times R.

    现在v等于ω,等于θ乘以

    youdao

  • So, that means what you're doing is you're fixing the value of theta.

    就是说固定θ

    youdao

  • Well, we do that by figuring out how b depends on theta when a is fixed.

    ,算ba不变的情形下,它是怎样依赖于θ?

    youdao

  • Plus the potential energy, which is mg times R times one minus cosine theta.

    加上势能,也就是mg乘以R乘以,1/cosθ

    youdao

  • This number can be larger than zero >0 if the sine theta is larger than zero.

    这个数字可以大于,只要sinθ

    youdao

  • dxdy Last time I told you if we have dx dy we could switch it to r dr d theta.

    上一次课提到,如果给出,我们可以转换rdrdθ

    youdao

  • The two flips out, which eats up this two, so I get mg R and then I get a theta.

    两个没用了,被抵消,所以得到mgR和θ

    youdao

  • If now we want to know what f prime is, f v/c plus v over c times the cosine of theta.

    若想知道f的大小,撇等于f乘以1,then,f,prime,equals,f,times,one,加上,乘以cosθ

    youdao

  • Now we forced this potential energy... we forced it into being dependent on theta squared.

    现在我们使得势能。,我们强迫,随着θ的平方而变

    youdao

  • So we get 2gl times the sine of theta mu k*cos 2 and the whole thing to the power one-half.

    所以我们得到2gl*sinθ,θ,minus,muofktimes,the,cosine,of,theta,所有项除以。

    youdao

  • Well, you could call that the rate of change of theta with respect to theta with a constant.

    可以称之为,保持a不变,θ关于θ自身变化率。

    youdao

  • Since there is no acceleration in the y direction, the normal force must be also mg cosine theta.

    既然y方向上,没有加速度,法向等于mgcosθ

    youdao

  • The velocity of that object as a function of theta is given Rd And I can make you see that very easily.

    物体速度,θ关系,θ/dt,by,R,d,theta/dt。,你们简单

    youdao

  • Then this is the component in your direction we call that the radial component which is v cosine theta.

    y方向的,组成因素,我们称之为辐射组成,等于vcosθ

    youdao

  • R And the track has a radius R, and at this moment in time the angle equals theta, and here is the object.

    轨道半径是这个时刻,角度等于θ,物体

    youdao

  • So, we set this to be zero. Theta, well, we are very happy because we want to express things in terms of theta.

    所以我们令它等于好,我们高兴因为我们就是θ表示

    youdao

  • This is a constant, and so you're going max to get theta equals theta maximum times the cosine omega t plus phi.

    不变的,所以得到θ=θ,乘以cosωt

    youdao

  • So it is this component, v cosine theta - which we call the radial velocity-- that is minus 100 kilometers per second.

    这个成分是vcosθ,我们叫做径向速度-,等于-100,公里每秒

    youdao

  • Meanwhile, the anti-X particle decays either to an antineutron or to two "hidden" antiparticles: anti-Y and anti-theta.

    同时个反“X”粒子要么变成一个反中子,要么衰变成两个未知的粒子:反“Y”粒子反“θ”粒子。

    youdao

  • See, this is the same formula as the one over there, just dividing everything by partial theta and with subscripts little a.

    那边公式一样的,只是通过θ和下标a把所有的事情分开,如果对你来说用这种方法更容易理解。

    youdao

  • Say, polar coordinates. Let's say that I have a function but is defined in terms of the polar coordinate variables on theta.

    比如说极坐标一个函数,根据极坐标θ定义

    youdao

  • Or, the other way around, I have a function of x and y and I want to express it in terms of the polar coordinates r and theta.

    反过来一个关于xy函数,可以表示极坐标r和θ

    youdao

  • So, it is possible to treat -1 as a constant input whose weight, theta, is adjusted in learning, or, to use the technical term, training.

    所以我们可以-1看成一个常量输入系数theta学习或者技术术语,称为 培训)的过程中进行调整。

    youdao

  • So, it is possible to treat -1 as a constant input whose weight, theta, is adjusted in learning, or, to use the technical term, training.

    所以我们可以-1看成一个常量输入系数theta学习或者技术术语,称为 培训)的过程中进行调整。

    youdao

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