There is no need to call [super init] in the second function, assuming these are both on the same class, which I inferred due to your comment.
没有必要在第二函数调用[超级初始化],假设这些都在同一班,我推断出由于你的评论。
There is no need to call [super init] in the second function, assuming these are both on the same class, which I inferred due to your comment.
没有必要在第二函数调用[超级初始化],假设这些都在同一班,我推断出由于你的评论。
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