• Determines whether a given type is a pointer to member object type.

    判定一个给定类型是否成员对象指针类型。

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  • Only arithmetic, enumeration, pointer, pointer to member, and class type arguments are allowed.

    只有算术枚举指针指向成员允许类型参数

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  • Finally, it creates an inquiry context for group member and sets the member name syntax field in the inquiry context structure and returns pointer to created inquiry context structure to the caller.

    最后为组成员创建查询上下文设置查询上下文结构中的成员语法字段创建查询上下文结构的指针返回调用者

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  • Casting from member function pointer to another type and back, strict-aliasing issue?

    铸造成员函数指针另一个类型背部,严格的混问题

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  • Unfortunately it is not possible to use pointer containers with mutating algorithms from the standard library. However, the most useful ones are instead provided as member functions.

    不幸可以指针容器标准可变算法共用。不过这些算法中最有用的已经成员函数的方式提供出来了。

    youdao

  • If the base member took different arguments than the derived-class member, there would be no way to call the derived function from a reference or pointer to the base type.

    如果成员派生类成员接受实参不同没有办法通过基类类型引用指针调用派生函数

    youdao

  • How can I use a private member variable in a non-member function, when the variable happens to be a pointer?

    如何非成员函数使用私有成员变量,变量指针

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  • If you have a pointer to a structure and the value of the pointer is correct, every member variable of the structure will show the correct value.

    如果指向结构指针而且指针正确的,那么结构的每个成员变量都将显示正确值。

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  • If I have a pointer to an object cast to one of its base classes, I can call the correct member functions through the abstract base class.

    如果一个对象指针,转换指针对象上,我通过基类指针调用合适成员函数

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  • How do I declare and use a pointer to a class member function?

    如何申报使用一个指向成员函数

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  • Traditional data partition ways are not suitable to pointer array whose member points to an array, so this paper presents a new mode to solve this problem, named array-vector data partition mode.

    传统数据划分模式适合指向数组的指针数组的数据划分,论文提出解决该类指针数组数据划分的划分模式,文中称为数组向量的数据划分。

    youdao

  • This error can be caused by a missing type specifier in the declaration of a pointer to a member.

    造成这项错误原因可能是:成员指标宣告遗漏别规范

    youdao

  • The line began with a pointer-to-member identifier.

    成员指标识别项开头。

    youdao

  • The line began with a pointer-to-member identifier.

    成员指标识别项开头。

    youdao

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