Does it exist that there is an extremely not BCI-Subodinate to BCH-Algebra. As a result, it is the conclusion that the finite BCI-Algebra discussed in (2) is nothing but odd Nil-radical.
是否存在极不bci的BCH -代数给出了答案，同时得到一个结论：对在(2)中所讨论的有限bci -代数，均是奇诣零代数。
Does it exist that there is an extremely not BCI-Subodinate to BCH-Algebra. As a result, it is the conclusion that the finite BCI-Algebra discussed in (2) is nothing but odd Nil-radical.
是否存在极不bci的BCH -代数给出了答案，同时得到一个结论：对在(2)中所讨论的有限bci -代数，均是奇诣零代数。
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