将会话密钥s分解成S1与S2之和。在大整数分解困难问题的条件下,构造特殊等式来解密s1(方案1)。
The session key s is divided into the sum of S1 and S2. Under the condition of a large integer factoring problem, S1 is decrypted by constructing a special equation (scheme 1).
将会话密钥s分解成S1与S2之和。在大整数分解困难问题的条件下,构造特殊等式来解密s1(方案1)。
The session key s is divided into the sum of S1 and S2. Under the condition of a large integer factoring problem, S1 is decrypted by constructing a special equation (scheme 1).
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